Society of Robots - Robot Forum
Electronics => Electronics => Topic started by: rabadswompe on September 17, 2010, 06:45:16 AM
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I can't figure the value of the resistor that is supposed to be soldered-in next to the led.
The parts list specifies 2 different resistors (in packs of 5) 1.62 k ohm and 340 ohm BUt the instructables steps don't mention the value...just to bend the metal pins 90°, solder and not cut them off. Yes... it took just that to stop me in my tracks :(
at the same time, the resitors mounted just behind the photoresistors... what value are they ????
Also, I did order from digikey and got my resistors but none are the same colour as the on in the pic... values are as asked though.
please help
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ok... i found my info on this thread :
http://www.societyofrobots.com/robotforum/index.php?topic=4737.0 (http://www.societyofrobots.com/robotforum/index.php?topic=4737.0)
the 340 ohm goes next to the LED and the 1.62 k ohm go to the photoresistors. right?????
are resistors polarized ? It think they're not but still, more prudent to ask.
only one worry... the colour coding. CAN resistors from diff makers/sellers have same value but diff colour ?
Learning as I go
Yann
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Resistors are not polarized.
Differences in the color code may be because your resistor has fewer or more stripes. For now just write down the colors of a resistor and the value (taken from a package) in your notes just to keep from being confused. It might be simple enough to note that of the two resistors only the 340 has a yellow stripe, for instance. Later, though, you should learn the resistor color code. There are hundreds of web sites that will help if you google for "resistor color code".
(http://i157.photobucket.com/albums/t53/FlyVote/clr_code.gif)
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super! Thanks GearMotion!
i must say tha the patience and helpfulness of the members of this forum is examplery and really keep newbees like myself at work and learning.
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super! Thanks GearMotion!
i must say tha the patience and helpfulness of the members of this forum is examplery and really keep newbees like myself at work and learning.
Always glad to help!