Society of Robots - Robot Forum
Mechanics and Construction => Mechanics and Construction => Topic started by: yatsu86 on July 25, 2007, 10:23:55 PM
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ok if you would use this formula to figure out wheel diameter then u could use it for finding a rpm right
example
3 ft/s = diameter * pi * 100rpm
3 ft/s = diameter * pi * 1.67rps (rotations per second)
diameter = 3 ft/s / (3.14 * 1.67 rps)
diameter = 0.57 ft, or 6.89"
real
3 ft/s= 3" *pi *rpm
3 ft/s= 9.42*rpm
rpm= 3 ft/s / 9.42
rpm= 3.18 ft/s or 19.12 rpm
but if u check the math it is not right or did i do my math wrong.
checking
3 ft/s = diameter * pi * 19.12rpm
3 ft/s = diameter * pi *.318rps (rotations per second)
diameter = 3 ft/s / (3.14 * .318 rps)
diameter =3.00 ft, or 36"
admin edit: Changed the subject 'i have a ?' to something more useful.
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You have to be careful with your units on this.
36"/s= 3" *pi *rps
36"/s= 9.42*rps
rps= 36"/s / 9.42
rps= 3.82 rotations per second.
Try to use the same units of length and time throughout your calculation.(eg. inches and seconds)