Author Topic: A/C adapter question  (Read 530 times)

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Offline MossenTopic starter

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A/C adapter question
« on: October 22, 2010, 12:41:51 PM »
Hi,
This is more of a general electronics question rather than specific to robots, but I was wondering:

When you see an A/C adapter and it says "output: 3.6V-7.2V" what does that mean? Can the output voltage be adjusted somehow? How does it work?

This is what I'm referring to:
http://www.servocity.com/html/3_6-7_2v_nicad___nimh_peak_cha.html

Offline rbtying

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Re: A/C adapter question
« Reply #1 on: October 22, 2010, 05:15:28 PM »
It means that the charger will charge batteries with varying cell counts, from 3 cell ( 3cell * 1.2 V/cell=3.6V) to 6 cell (6 * 1.2 = 7.2V).  It will automatically adjust to your battery, usually.

Offline Soeren

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Re: A/C adapter question
« Reply #2 on: October 23, 2010, 12:06:21 PM »
Hi,

This is what I'm referring to:
http://www.servocity.com/html/3_6-7_2v_nicad___nimh_peak_cha.html

That's not an AC adapter, it's a charger (large difference, although they look fairly alike).
Regards,
Søren

A rather fast and fairly heavy robot with quite large wheels needs what? A lot of power?
Please remember...
Engineering is based on numbers - not adjectives

Offline z.s.tar.gz

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Re: A/C adapter question
« Reply #3 on: October 23, 2010, 10:07:36 PM »
Yep. Although it contains the circuitry of an AC adapter you can't use it as a dc power source because there's a battery charging circuit standing between you and that raw energy.
Save yourself the typing. Just call me Zach.

 


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