output binary to selected pins

[blackbeard]

ok so i have an led cube i'm trying to program. essentially i've got 2 8 bit dmux connected to 3 i/o on the arduino and the inputs connected to 2 other pins. my problem is that i don't always want to have this kind of thing in my code. i'd much rather just say a binary number to write to the pins that the mux is connected to

digitalWrite(muxS1, HIGH);
digitalWrite(muxS2, LOW);
digitalWrite(muxS3, LOW);

digitalWrite(muxS1, LOW);
digitalWrite(muxS2, HIGH);
digitalWrite(muxS3, LOW);

[madsci1016]

How about

for(int value = 0; value <=7; value++){

digitalWrite(muxS1, bitRead(value, 0));
digitalWrite(muxS2, bitRead(value, 1));
digitalWrite(muxS3, bitRead(value, 2));

}

That will set the three pins to the state described by the lower three bits in the value number. With the loop, it will cycle through all the outputs of your demux.

[blackbeard]

How about

for(int value = 0; value <=7; value++){

digitalWrite(muxS1, bitRead(value, 0));
digitalWrite(muxS2, bitRead(value, 1));
digitalWrite(muxS3, bitRead(value, 2));

}

That will set the three pins to the state described by the lower three bits in the value number. With the loop, it will cycle through all the outputs of your demux.

thanks allot. that's allot better then the code i am using now which looks something like this it's random but that's just so i can test the whole cube.

  count = random(0,8);
  row = bin[count];
  mux1= row & 0x01;
  mux2 = (row>>1) & 0x01;
  mux3 = (row>>2) & 0x01;
  digitalWrite(7, mux1);
  digitalWrite(8, mux2);
 digitalWrite(9, mux3);