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### Author Topic: using shunt resistor to measure high DC current  (Read 5676 times)

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#### BANE

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##### using shunt resistor to measure high DC current
« on: June 08, 2011, 08:01:27 AM »
This is my first time attemping to use a shunt resistor to measure high DC current.  I just wanted to get some advice on whether or not this is a good idea.
My power supply is 6x 12v 33ah lead acid batteries and load is 3x sabertooth 2x50HV motor drivers driving 6 wheelchair motors.
Here is a pic of what a shunt resistor looks like for those who dont know (like me before;))
After doing research i found this video and thought it would be perfect for my application.
#44 Poor Man's DC shunt to measure high current

My question: the out put on the shunt is in mV and i need to get this in the 2.5V range for the axon II.  Do i need a op amp or something to get this into the correct range?

any two cents is appreciated as always
« Last Edit: June 08, 2011, 08:04:12 AM by BANE »

#### rbtying

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##### Re: using shunt resistor to measure high DC current
« Reply #1 on: June 08, 2011, 08:51:12 AM »
An op-amp would be a good idea, yes.  Although, at the currents you're measuring, you'd probably be better off with a hall-effect current sensor: 3*2*50A*12v = 3600W at max load... and 50A*50A*(resistance) is going to be a rather large value to dissipate over the shunt.

Who knows... you may even have the shunt resistor desolder itself (xD)

#### BANE

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##### Re: using shunt resistor to measure high DC current
« Reply #2 on: June 08, 2011, 09:50:31 AM »
thanks for the response rbtying.

Also, the battery configuration will be wired for 36v @ 66Ah.

Quote
hall-effect current sensor:
I remember studying this in physics class and this may be a better route.
http://carrott.org/blog/archives/111-Measuring-charge-current.html
this is what you're talking about right?

edit:  a little bit more about the load. According to my motor driver http://www.dimensionengineering.com/Sabertooth2x50HV.htm
each of these can peak out at 100A per channel for a couple seconds.  Times 6 and that's 600A spike.  Which seems rather large but that is why I want to figure out how much these babies are actually drawing.
« Last Edit: June 08, 2011, 09:56:36 AM by BANE »

#### Soeren

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##### Re: using shunt resistor to measure high DC current
« Reply #3 on: June 08, 2011, 12:28:39 PM »
Hi,

My power supply is 6x 12v 33ah lead acid batteries and load is 3x sabertooth 2x50HV motor drivers driving 6 wheelchair motors.
[...]
My question: the out put on the shunt is in mV and i need to get this in the 2.5V range for the axon II.  Do i need a op amp or something to get this into the correct range?
It's not the best idea to use a shunt with such high currents.
If both sides of a Sabretooth can peak at 100A each, a 1mOhm shunt will dissipate 40W (120W when all 6 motors start)
But considering the low percentage of the total, it may be bearable - just don't use a homemade shunt - it should be rated for the max. current it's likely to see and anything above 1mOhm will be bad (with 10mOhm you'd dissipate 1.2kW at start-up).

You cannot go that much lower either, if you want to be able to measure low draws with any kind of precision (and you'll be hard pressed to find a shunt that low anyway).

And yes, you'd need an op-amp following it - a rather specialized circuit , if you intend the shunt to go into the positive line, but want the output to be ground referenced for the A/D-C to read.

This is a typical case for a Hall effect current sensor and here is a couple of links (you still need them beefy enough to withstand the max. current).
LEM
And here is a page on the LEM transducers as well (perhaps it has some further info).

http://scienceshareware.com/how-to-measure-AC-DC-current-with-a-hall-effect-clamp-.htm

That said... You might wanna check the price on those monsters
http://parts.digikey.com/1/parts/1376224-sensor-current-200a-24v-uni-mod-apr-200-b10.html

Ouch - suddenly a short rod of konstantan or similar makes sense

And... If precision isn't too important, you could use some stainless steel welding rods and make a shunt yourself - will be hard to calibrate without a reference though.

If it's just for getting some initial measurements, consider if you can borrow a suitable Hall based (to measure DC) clamp meter somewhere.

I didn't watch the video, but forget anything as fragile as the shunt shown at the initial pic..
Regards,
Søren

A rather fast and fairly heavy robot with quite large wheels needs what? A lot of power?
Engineering is based on numbers - not adjectives

#### BANE

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##### Re: using shunt resistor to measure high DC current
« Reply #4 on: June 08, 2011, 07:31:30 PM »
Quote
Ouch - suddenly a short rod of konstantan or similar makes sense
yep
Quote
stainless steel welding rods and make a shunt yourself - will be hard to calibrate without a reference though.
I hadnt thought of using stainless.  less resistance i can assume.  As far as getting my numbers, i thought about using my muiltymeter that can measure current up to 10amps and get a graph with my oscope and extrapolate the rest of the data to 200A.  However, its probably not linear but maybe some overall trend.

After research, i think im going to contact a local electrician and ask to rent clamp meter or something
Quote
If it's just for getting some initial measurements, consider if you can borrow a suitable Hall based (to measure DC) clamp meter somewhere.
you're always one step ahead damnit

• Supreme Robot
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##### Re: using shunt resistor to measure high DC current
« Reply #5 on: June 09, 2011, 10:46:04 PM »
Not for the poor man, but SF sells this:
http://www.sparkfun.com/products/9028

It uses "a pair of parallel 1 mOhm shunt resistors" . . .