code for simple line follower using switch case

[V!KR@M]

Hello everyone, I'm new to robotics and i'm trying to write a line follower robot code using switch case

The problem comes with case statement. That is if i use 3 line sensors, i get 3 inputs. So how can i write switch case for different cases? Like..

Code: [Select]

case 101:
break;
 case 110:
break;

Before going ahead, the code i have tried for testing:

Code: [Select]

int s[1]; //2 sensors
void setup()
{
  pinMode(2, INPUT);
  pinMode(12, INPUT);
  pinMode(13, OUTPUT);
}
void loop()
{
  s[0]= digitalRead(2);
  s[1]= digitalRead(12);

  switch (s[])
{
case {1,0}:
digitalWrite(13, LOW);//led connected to pin 13
break;

case {1,1}:
digitalWrite(13, HIGH);
break;

}
}
But it shows the error : expected primary expression before ']' token.
Looks like the switch statement doesn't take array.
Is there a way to do with switch case or it's not possible? How to combine all the inputs from sensors and put it in switch statement?

I hope i have expressed properly. Any help would be appreciated.
Sorry for my bad english

[adanvasco]

The switch statement expects a reference to a value to compare to your case. Thus, it can use an array, but only if it knows exactly to what index refer to. What I mean is that the switch does not now what value from your array to use for comparison. The switch statement works with a single variable, and an array is basically a collection of variables.

[ebrady]

You can not use an array with a case statement.  The easiest method would be to convert your input data into a single int using shift and add.  Here is a modified verions of your original code.

Code: [Select]

int s; //2 sensors
void setup()
{
  pinMode(2, INPUT);
  pinMode(12, INPUT);
  pinMode(13, OUTPUT);
}
void loop()
{
  s = digitalRead(2);  //Read Pin 2 into s
  s = (s << 1) + digitalRead(12); //Shift s one and add pin 12 

//At this point s contains a value from 0 - 3 which is a 2 bit representation of the two pins.
//Use s in your switch statement and act on it as a single int.

switch (s)
{

case 0: // This is the { 0,0 } case
break;

case 1: // This is the { 0,1 } case
break;

case 2:  //This is the { 1,0 } case
digitalWrite(13, LOW);//led connected to pin 13
break;

case 3:  //This is the { 1,1 } case.
digitalWrite(13, HIGH);
break;

default:
break

}
}
Hope this helps

[V!KR@M]

You can not use an array with a case statement.  The easiest method would be to convert your input data into a single int using shift and add.  Here is a modified verions of your original code.

Code: [Select]

int s; //2 sensors
void setup()
{
  pinMode(2, INPUT);
  pinMode(12, INPUT);
  pinMode(13, OUTPUT);
}
void loop()
{
  s = digitalRead(2);  //Read Pin 2 into s
  s = (s << 1) + digitalRead(12); //Shift s one and add pin 12 

//At this point s contains a value from 0 - 3 which is a 2 bit representation of the two pins.
//Use s in your switch statement and act on it as a single int.

switch (s)
{

case 0: // This is the { 0,0 } case
break;

case 1: // This is the { 0,1 } case
break;

case 2:  //This is the { 1,0 } case
digitalWrite(13, LOW);//led connected to pin 13
break;

case 3:  //This is the { 1,1 } case.
digitalWrite(13, HIGH);
break;

default:
break

}
}
Hope this helps

Ok i understand. But does it do a binary addition or decimal addition?
Like what does it do when it comes across an addition like 101+1. Does it give 110 or 102?

[ebrady]

Ok i understand. But does it do a binary addition or decimal addition?
Like what does it do when it comes across an addition like 101+1. Does it give 110 or 102?

There really isn't a such thing as binary addition or decimal addition.  There is only "addition".  What you are asking about, is what kind of value does s represent, a decimal or binary number. In the case of the example I posted, think of all of the additions as being "decimal addition".