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so, what does the AREF pin do
you want 2v dropping at 10mA. 2 / .01You need 200 Ohms
negative.When calculating a series resistor you take how much voltage you want it to drop and then how much current you want it to have going through it and plug it into ohms law. so:Vdrop / Icircuit = Rseries
Now that I think about it , there is not much difference (for my application, at least) from using a 5V supply and a 3V supply assuming 10 bit ADC at 5V I have resolution of 5/1024 = .005V each stepat 3V I have resolution of 3/1024 = .003V each step@SoerenI learned it a while ago , and haven't really needed those laws that badly until now. I have a program called Electronics Assistant which calculates the proper resistor values, capacitor values , etc. after you enter in some values of your own. Having a program do all my calculations for me (like just this morning I used it to calculate the proper resistor for a high power LED)I realized how bad I am in these laws, so I plan to review it over this weekend.
Why on earth not just go with the internal reference?