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What exactly is the charge current anyways?
The batteries will be in series, so if I just apply 7.8V @ 1.1A all the time, I would just have to monitor it to tell when it's done aka at 3%?Sorry, it still doesn't make much sense to me.
Hi,Take a look at this circuitIt will do the CC/CV (a better name for that would be max. current and max. voltage) you need.You could modify it for a switch mode regulator - the resistor values need changing anyway.
You won't need the 4 diodes on the left side of the circuit, that is only for AC input. And using a R]resistive regulator is a waste of energy.
Soeren, I'm assuming you know of switch mode regulators the accept an input reference for voltage output.
Not quite sure what you mean?
I see...For the sake of free day from sparkfun I'm going to go with the parts I linked to earlier, but if that doesn't work out I'm going to use that one you posted.
The LM317 is that circuit is a resistive regulator. It drops voltage down by burning it off in a resistor, just like the 7805 (etc) voltage regulator.
The LM317 is an adjustable regulator. The circuit you provided work as a CC source because the the LM317 is electronically adjusted to maintain the correct voltage based on current. If he were to adapt this circuit to a switching regulator, he would need one that had a input pin that controlled it's output voltage like the LM317 does. I guess the solution to this is two build a switching regulator circuit, as opposed to a pre built regulator.
No, it's called a linear regulator and it dissipates the dropped power in a semiconductor (just like the 78xx and any other linear regulators).