Author Topic: DC motor  (Read 5790 times)

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Offline dsesmgTopic starter

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Re: DC motor
« Reply #30 on: August 21, 2009, 07:24:25 PM »
Hi, thanks a lot.
I just tested with the circuit you proposed and it works great.
when I exposed the photo transistor to the sunlight, the motor spins.
Also, when i beam TV remote control light to the photo transistor, the motor spins a little.
I think it is because, the TV remote control doesn't beam the light continuosly even if I keep the button pressed.
I hope i could make a circuit for the infrared emitter and test with this photo transistor circuit.
As you know, the current emitter i have is this specification.
http://www.flickr.com/photos/34955071@N02/3825092211/sizes/o/
http://www.flickr.com/photos/34955071@N02/3825079541/sizes/o/
http://www.flickr.com/photos/34955071@N02/3825092215/sizes/o/
http://www.flickr.com/photos/34955071@N02/3825079427/sizes/o/
But, I have little knowledge about this.
I need to control this emitter by using some microcontroller signal.
Could you advise me how to wire up the emitter?

Offline SmAsH

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Re: DC motor
« Reply #31 on: August 22, 2009, 01:54:50 AM »
wait, what do you want to control?
the current flow from the collector to emitter?
there you will put the base to a digital pin... am i getting you?
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Offline dsesmgTopic starter

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Re: DC motor
« Reply #32 on: August 22, 2009, 02:02:31 AM »
Hi, James,
Yes, I need to control the current flowing from the collector to emitter so that I can control the on/off mode of the emitter.
Yes, I will put a digital pin to the base of the TIP102 so that the TIP102 transistor could act like a switch. :)

Offline dsesmgTopic starter

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Re: DC motor
« Reply #33 on: August 22, 2009, 02:05:55 AM »

Offline SmAsH

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Re: DC motor
« Reply #34 on: August 22, 2009, 02:11:26 AM »
yeah, that will work...
just a word, you don't need the diode if you are controlling something like an led...
the diode is just to stop back emf from motors or other coils.
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Offline dsesmgTopic starter

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Re: DC motor
« Reply #35 on: August 22, 2009, 02:20:06 AM »
Thanks a lot, James.
OK, I will take out the 1N4004.
I will test with this circuit and I will get back with the result. :)

Offline SmAsH

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Re: DC motor
« Reply #36 on: August 22, 2009, 02:27:14 AM »
ok, your testing it with a microcontroller right?
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Offline Soeren

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Re: DC motor
« Reply #37 on: August 22, 2009, 09:02:11 PM »
Hi,

yeah, that will work...
... If a LED with internal current limiting is used, yes, otherwise, just for a split second ;D
Regards,
Søren

A rather fast and fairly heavy robot with quite large wheels needs what? A lot of power?
Please remember...
Engineering is based on numbers - not adjectives

Offline SmAsH

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Re: DC motor
« Reply #38 on: August 22, 2009, 09:05:36 PM »
why is that, because of no resistor?
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Offline Soeren

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Re: DC motor
« Reply #39 on: August 22, 2009, 09:24:14 PM »
Yes.
Regards,
Søren

A rather fast and fairly heavy robot with quite large wheels needs what? A lot of power?
Please remember...
Engineering is based on numbers - not adjectives

Offline dsesmgTopic starter

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Re: DC motor
« Reply #40 on: August 22, 2009, 10:18:52 PM »
Hi, yes,I am using it with a microcontroller.
then, how much ohm resistor do I need to use?
Because, I tested with the circuit after taking out 1N4004 from the circuit.
The emitter doesn't show any result.
So, I replaced the emitter with a normal LED. The LED blinked well so I brought it close to the transistor and the motor spinned very well.
I thought the emitter is broken or something.
Could you advise me how much ohm do I need to use and where should it be connected?

Also,the photo transistor only responded to red colored LED.
I have red,green, yellow LEDs and tested with them all.
Anyway, only the red colored LED is giving effect on the photo transistor.
« Last Edit: August 22, 2009, 10:20:10 PM by dsesmg »

Offline SmAsH

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Re: DC motor
« Reply #41 on: August 22, 2009, 10:25:00 PM »
well, if you are giving the led 5v as your supply i would say something in the 150-250 ohm region would work well.
the resistor should just be placed in between the led +(anode) and your supply.

the reason it only reacts to certain leds is because of its operating wavelengths...
it will only turn on with wavelengths from a certain range. the leds that work must be in that range ;)
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Offline dsesmgTopic starter

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Re: DC motor
« Reply #42 on: August 22, 2009, 11:03:45 PM »
Thanks a lot, James.
Then, I will test it with 150~250 ohm resistors.
I don't have them right now, so I will order them today.
By the way, I am trying to find better emitter and detector.
Below is the emitters.
* S13317-H
http://www.flickr.com/photos/34955071@N02/3847545598/sizes/o/
http://www.flickr.com/photos/34955071@N02/3846755227/sizes/o/
http://www.flickr.com/photos/34955071@N02/3846755305/sizes/o/

* EL-1CL3
http://www.eleparts.co.kr/epdf/SENSOR/EL-1CL3.pdf

And below is the detectors.
* SP-1CL3
http://www.eleparts.co.kr/epdf/SENSOR/SP-1CL3.pdf
* ST-1CL3H
http://www.eleparts.co.kr/epdf/SENSOR/ST-1CL3H.pdf

I am trying to choose one of those emitters and detectors.
I don't quite familiar with the specification of such sensors.
Could you advise me which emitter has the longest beaming distance and which detector is less sensitive to the visible light?


Offline SmAsH

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Re: DC motor
« Reply #43 on: August 22, 2009, 11:25:14 PM »
dude! do you have enough programs open :P

well, you will want to look for a set that are in the same wavelength...
if you want them not to be too affected by visible light then go for a pair in the infrared spectrum...
i cant really give advice on those ones as i think i have a virus or something thats screwing with my adobe >:(
as far as range goes, try to go for a non-diffused emitter as it is generally brighter...

as for the resistors, they will need to change according to your emitters, use the following formula to choose
a resistor: supply_voltage-led_operating_voltage/led_operating_current_in_amps...
eg 5-2=3, 3/.02=150... resistor =150 ohms.
remember to recalculate accordingly...
Howdy

Offline dsesmgTopic starter

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Re: DC motor
« Reply #44 on: August 23, 2009, 02:35:59 AM »
Thank you, James.
It's very helpful.  :)

 


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