# Ex 6.3, 9 - Chapter 6 Class 8 Squares and Square Roots

Last updated at Sept. 11, 2018 by Teachoo

Last updated at Sept. 11, 2018 by Teachoo

Transcript

Ex 6.3, 9 Find the smallest square number that is divisible by each of the numbers 4, 9 and 10. Smallest square number divisible by 4, 9 and 10 = L.C.M of 4, 9 and 10 OR Multiple of L.C.M Finding L.C.M of 4, 9, 10 L.C.M of 4, 9, 10 = 2 × 2 × 3 × 3 × 5 = 4 × 9 × 5 = 180 Checking if 180 is a perfect square We see that 180 = 2 × 2 × 3 × 3 × 5 Since 5 is not in pair, ∴ 180 is not a perfect square. So, we multiply by 5 to make pairs So, our number becomes 180 × 5 = 2 × 2 × 3 × 3 × 5 × 5 900 = 2 × 2 × 3 × 3 × 5 × 5 Now, it becomes a perfect square. Thus, required number is 900

Ex 6.3

Ex 6.3, 1 (i)

Ex 6.3, 1 (ii)

Ex 6.3, 1 (iii)

Ex 6.3, 1 (iv)

Ex 6.3, 2 (i) Important

Ex 6.3, 2 (ii)

Ex 6.3, 2 (iii)

Ex 6.3, 2 (iv)

Ex 6.3, 3 Important

Ex 6.3, 4 (i) Important

Ex 6.3, 4 (ii)

Ex 6.3, 4 (iii)

Ex 6.3, 4 (iv)

Ex 6.3, 4 (v)

Ex 6.3, 4 (vi)

Ex 6.3, 4 (vii)

Ex 6.3, 4 (viii)

Ex 6.3, 4 (ix)

Ex 6.3, 4 (x)

Ex 6.3, 5 (i)

Ex 6.3, 5 (ii)

Ex 6.3, 5 (iii)

Ex 6.3, 5 (iv)

Ex 6.3, 5 (v)

Ex 6.3, 5 (vi)

Ex 6.3, 6 (i)

Ex 6.3, 6 (ii)

Ex 6.3, 6 (iii)

Ex 6.3, 6 (iv)

Ex 6.3, 6 (v)

Ex 6.3, 6 (vi)

Ex 6.3, 7

Ex 6.3, 8

Ex 6.3, 9 You are here

Ex 6.3, 10 Important

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.