Society of Robots - Robot Forum
Mechanics and Construction => Mechanics and Construction => Topic started by: maxhirez on October 18, 2011, 09:36:42 PM
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I must not be entering the right search terms in Google. I'm trying to figure out what the effective lifting capacity of a joint with a servo rated at a given torque will be at various arm lengths. For simplicity's sake, let's use 350 oz/in. How would I calculate how many ounces that works out to at various arm lengths between 7-10 in? Wikipedia and my physics references books have been
USELESS!
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I must not be entering the right search terms in Google. I'm trying to figure out what the effective lifting capacity of a joint with a servo rated at a given torque will be at various arm lengths. For simplicity's sake, let's use 350 oz/in. How would I calculate how many ounces that works out to at various arm lengths between 7-10 in? Wikipedia and my physics references books have been USELESS!
Ahemm... I don't think it's the books and Wikipedia that's useless - probably just a 16" error (that's 16" in front of books/screen :D)
350 ozf-in means that it can handle up to 350 oz of force at a distance of 1"
At 5" it's thus 350/5 [oz]
At 8" it's 350/8 [oz]
An so on