Author Topic: Watt Hours :IGNORE: Figured it out  (Read 2391 times)

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Offline soninja8Topic starter

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Watt Hours :IGNORE: Figured it out
« on: July 12, 2011, 12:12:10 AM »
Edit: Figured Out My Problem
« Last Edit: July 12, 2011, 12:16:17 AM by soninja8 »
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Offline mstacho

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Re: Watt Hours :IGNORE: Figured it out
« Reply #1 on: July 12, 2011, 08:23:06 AM »
Actually, since you had the question, it stands to reason that someone else might have the same question in the future.  If you post the question and your solution, it might help someone who's searching for it, even if it seems basic! :-)

MIKE
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Offline soninja8Topic starter

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Re: Watt Hours :IGNORE: Figured it out
« Reply #2 on: July 12, 2011, 12:09:53 PM »
Quote from: mstacho on July 12, 2011, 08:23:06 AM
Actually, since you had the question, it stands to reason that someone else might have the same question in the future.  If you post the question and your solution, it might help someone who's searching for it, even if it seems basic! :-)

MIKE

Never though of that, well my question was how do I know what 55 watt hours means in milli-amps. And to figure this out, you take the watt-hours, which in my case was 55, and divide it by the voltage of the same battery, for me was 10.8v, and times the number you get by a 1000, and thats how many milli-amps it is, which ended up being around 5000mah for me.
Correct?

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Offline corrado33

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Re: Watt Hours :IGNORE: Figured it out
« Reply #3 on: July 12, 2011, 02:20:05 PM »
Just keep in mind, milliamps and milliamp HOURS are two different things.  One is a measure of current while the other is a measure of capacity/charge (I think). 
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Offline waltr

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Re: Watt Hours :IGNORE: Figured it out
« Reply #4 on: July 12, 2011, 02:34:37 PM »
Yep, they are two different measures. Use the units to help convert.

Watt-Hour = (Volts * Amps) * Hours
so to convert to milliAmp you need to remove the Volt and Hour units by dividing them out then convert to milli by multiplying by 1000. So you also need to know how many hours the Watts were measured over as well as the voltage.
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